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Magnetic flux passing through a coil var...

Magnetic flux passing through a coil varies with time as, `phi=(2t^(2)-4)` weber, Resistance of the coil is `10Omega`.

A

At time t=2s, induced current in the coil is 0.8A

B

Induced current increases lineraly with time

C

From t=0 to t=2s,0.8C charge has flown in the coil

D

in the above time interval net flow of charge is zero

Text Solution

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The correct Answer is:
To solve the problem step by step, we will analyze the given magnetic flux equation and calculate the induced current, charge flow, and check the validity of the options provided. ### Given: - Magnetic flux, \( \phi(t) = 2t^2 - 4 \) Weber - Resistance of the coil, \( R = 10 \, \Omega \) ### Step 1: Calculate the induced EMF The induced EMF (\( \mathcal{E} \)) can be calculated using Faraday's law of electromagnetic induction, which states that the induced EMF is equal to the rate of change of magnetic flux: \[ \mathcal{E} = -\frac{d\phi}{dt} \] First, we need to differentiate the magnetic flux with respect to time \( t \): \[ \frac{d\phi}{dt} = \frac{d}{dt}(2t^2 - 4) = 4t \] Thus, the induced EMF is: \[ \mathcal{E} = -4t \] ### Step 2: Calculate the induced current at \( t = 2 \) seconds Now, we will find the induced current (\( I \)) using Ohm's law: \[ I = \frac{\mathcal{E}}{R} \] Substituting \( t = 2 \) seconds into the EMF equation: \[ \mathcal{E} = -4(2) = -8 \, \text{V} \] Now, using the absolute value of EMF (since current is a scalar quantity): \[ I = \frac{8}{10} = 0.8 \, \text{A} \] ### Step 3: Check if the induced current increases linearly with time From the EMF equation, we have: \[ \mathcal{E} = 4t \] Thus, the induced current can be expressed as: \[ I = \frac{4t}{10} = 0.4t \] This shows that the induced current is directly proportional to time \( t \), indicating that it increases linearly with time. ### Step 4: Calculate the charge flow through the coil from \( t = 0 \) to \( t = 2 \) seconds The charge (\( Q \)) flowing through the coil can be calculated using the formula: \[ Q = \int_0^t I \, dt \] Using the expression for current: \[ Q = \int_0^2 0.4t \, dt \] Calculating the integral: \[ Q = 0.4 \int_0^2 t \, dt = 0.4 \left[ \frac{t^2}{2} \right]_0^2 = 0.4 \left[ \frac{2^2}{2} - 0 \right] = 0.4 \left[ 2 \right] = 0.8 \, \text{C} \] ### Step 5: Conclusion on the options - **Option A**: The induced current at \( t = 2 \) seconds is \( 0.8 \, \text{A} \) (Correct) - **Option B**: The induced current increases linearly with time (Correct) - **Option C**: The charge flow through the coil from \( t = 0 \) to \( t = 2 \) seconds is \( 0.8 \, \text{C} \) (Correct) - **Option D**: The net flow of charge is zero (Incorrect, as the net charge is \( 0.8 \, \text{C} \)) ### Final Answer: Options A, B, and C are correct, while option D is incorrect. ---
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