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A capacitor of capacitnace C is charged ...

A capacitor of capacitnace C is charged to a potential difference V and then disconnected from the battery. Now it is connected to an inductor of inductance L at t=0. Then

A

Energy stored in capacitor and inductor will be equal at time `t=(pi)/(2)sqrtLC`

B

Potential difference across inductor will be `(V)/(2)` at time `t=(pi)/(3)sqrtLC`

C

The rate of increase of energy in magnetic field will be maximum at `(pi)/(4)sqrtLC`

D

When the potentail difference across the capacitor `sqrt(((3C)/(L)))`

Text Solution

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The correct Answer is:
B, C, D
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