Write the dimensions of a and b in the relation ,` P = (b-x^(2))/(at)` , where P
is power ,x is distance and t is time

Explanation

The given equation can be written as,
`Pat=b-x^(2)`
Now, `[Pat]=[b]=[x^(2)]`
or `[b]=[x^(2)]=[M^(0)L^(2)T^(0)]`
and `[a]=([x^(2)])/([Pt])=([L^(2)])/([ML^(2)T^(-3)][T])=[M^(-1)L^(0)T^(2)]`