Find the value 15 joule in a system which has 10 cm, 100 gm and 20sec as a fundamental units?

Explanation

The dimensional formula of work is = `[ML^(2)T^(-2)]`
The convert a physical quantity from one system of units to other system of units, we use the following formula
`n_(2)=n_(1) [(M_(1))/(M_(2))]^(a)[(L_(1))/(L_(2))]^(c)[(T_(1))/(T_(2))]^("c")`
`n_(2)=100[(1 kg)/(250g)]^(1)[(1m)/(20cm)]^(2)[(1s)/(0.5 min)]^(-2)`
= `100 [(1000g)/(250g)]^(1)[(100m)/(20cm)]^(2)[(1s)/(30s)]^(-2)`
`100xx4xx25xx30xx30`
`9xx10^(6)` new units