Home
Class 11
PHYSICS
The diameter of a wire as measured by sc...

The diameter of a wire as measured by screw gauge was found to be 2.620, 2.625, 2.630, 2.628 and 2.626 cm. Calculate
(a) mean value of diameter (b) absolute error in each measurement
(c) mean absolute error (d) fractional error
(e) percentage error (f) Express the result in terms of percentage error

Text Solution

AI Generated Solution

To solve the problem step by step, we will calculate the mean value of the diameter, absolute error in each measurement, mean absolute error, fractional error, percentage error, and finally express the result in terms of percentage error. ### Step 1: Calculate the Mean Value of Diameter To find the mean value of the diameter, we sum all the measurements and divide by the number of measurements. Given measurements: - \( D_1 = 2.620 \, \text{cm} \) - \( D_2 = 2.625 \, \text{cm} \) ...
Promotional Banner

Topper's Solved these Questions

  • UNITS, DIMENSIONS & ERROR ANALYSIS

    DC PANDEY ENGLISH|Exercise Check Point 1.1|25 Videos
  • UNITS, DIMENSIONS & ERROR ANALYSIS

    DC PANDEY ENGLISH|Exercise Check Point 1.2|10 Videos
  • UNIT AND DIMENSIONS

    DC PANDEY ENGLISH|Exercise Assertion And Reason|2 Videos
  • VECTORS

    DC PANDEY ENGLISH|Exercise Medical enrances gallery|9 Videos

Similar Questions

Explore conceptually related problems

The diameter of a wire as measured by a Screw gauge was found to be 1.328, 1.330, 1.325, 1.326, 1.334 and 1.336 cm. Calculate (i) mean value of diameter (ii) absolute error in each measurement (iii) mean absolute error (iv) fractional error (v) percentage error. Also, express the result in term of absolute error and percentage error.

The diameter of a wire as measured by a screw gauge was found to be 0.026 cm, 0.028 cm, 0.029 cm, 0.027cm, 0.024cm and 0.027 cm. Calculate (i) mean value of diameter (ii) mean absoulte error (iii) relative error (iv) percentage error. Also express the result in terms of absolute error and percentage error.

The refractive index (n) of glass is found to have the values 1.49,1.50,1.52,1.54 and 1.48. Calculate (i) the mean value of refractive index, (ii) absolute error in each measurement, (iii) mean absolute error, (iv) fractional error and (v) percentage error

In successive measurement, the reading of the period of oscillation of a simple pendulum were found to be 2.63s, 2.56s, 2.71s and 2.80s in an experiment. Calculate (i) mean value of the period oscillation (ii) absolute errer in each measurement (iii) mean absolute error (iv) releative error (v) percentage error and (vi) express the result in proper form.

The diameter of a wire as measured by a screw gauge was found to be 1.002 cm, 1.000 cm, 1.006 cm .The absolute error in the second reading is

In an experiment the refractive index of glass was observed to be 1.45 , 1.56 , 1.54 , 1.44 , 1.54 , and 1.53 . Calculate (a). Mean value of refractive index (b). Mean absolute error ( c ) Fractional error (d) Percentage error (e) Express the result in terms of absolute error and percentage error

The length of a cylinder was measured using a vernier calipers several times. The following reading were obtained (in cm) : 1.12, 1.11,1.13, 1.10,1.14,1.15,1.16. Calculate (i) mean value of the length (ii) the absolute error in each measurement (iii) mean absolute error (iv) relative error and (v) percentage error. Write down the result in terms of mean absolute error and percentage error.

The values for the diameter of a wire as measured by a screw gauge were found to be 0.026 cm, 0.028 cm, 0.029 cm, 0.027 cm, 0.024 cm and 0.027 cm. Find the mean value and the relative error.

Following observations were taken with a vernier callipers while measuring the length of a cylinder : 3.29 cm,3.28 cm,3.31 cm,3.28 cm,3.27 cm,3.29 cm,3.20 cm . Then find : (a) Most accurate length of the cylinder (b) Absolute error in each observation (c) Mean absolute error (d) Relative error (e) Percentage error Express the result in terms absolute error and percentage error.

In an experiment the valno of refractive index of glass was found to be 1.54, 1.53, 1.44,1.54, 1.56 and 1.45 m in successive measurement. Calculate (i) the mean vlaue of refractive index (ii) absolute error of each measurement (iii) mean absolute error (iv) relative error and (v) percentage error.

DC PANDEY ENGLISH-UNITS, DIMENSIONS & ERROR ANALYSIS -Medical entrances gallery
  1. The diameter of a wire as measured by screw gauge was found to be 2.62...

    Text Solution

    |

  2. Force F is given in terms of time t and distance x by F = A sin Ct + B...

    Text Solution

    |

  3. The scalar quantity among the following is

    Text Solution

    |

  4. The wrong units conversion among the following is

    Text Solution

    |

  5. The mass of the liquid flowing per second per unit area of cross-secti...

    Text Solution

    |

  6. The ratio of the dimensions of Planck's constant and that of the momen...

    Text Solution

    |

  7. In terms of basic units of mass (M), length (L), time (T), and charge ...

    Text Solution

    |

  8. The dimensional formula of electric flux is

    Text Solution

    |

  9. If energy (E), velocity (v) and time (T) are chosen as the fundamental...

    Text Solution

    |

  10. Match the following two columns. {:(,"Column I",,"Column II"),("A.",...

    Text Solution

    |

  11. The unit of three physical quantities x, y and z are g cm^(2) s^(-5), ...

    Text Solution

    |

  12. The unit of universal gas constant is

    Text Solution

    |

  13. Unit of emf is

    Text Solution

    |

  14. The dimensional formula for Reynold's number is

    Text Solution

    |

  15. The relation between force F and density d is F=(x)/(sqrt(d)). The d...

    Text Solution

    |

  16. In which of the following pairs, the two physical quantities have diff...

    Text Solution

    |

  17. If the absoulte errors in two physical quantites A and B are a and b r...

    Text Solution

    |

  18. If force (F), velocity (V) and time (T) are taken as fundamental units...

    Text Solution

    |

  19. If the unit of force is 1 kN, unit of length 1 km and unit of time is ...

    Text Solution

    |

  20. The dimensional formula for magnetic flux is

    Text Solution

    |

  21. The dimensional formula for electric field is

    Text Solution

    |