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The dimensional formula fo resistivity i...

The dimensional formula fo resistivity in terms of `M,L,T` and `Q` where `Q` stands for the dimensions of charge is

A

`[ML^(3)T^(-1)Q^(-2)]`

B

`[ML^(2)T^(-2)Q^(2)]`

C

`[MLT^(-2)Q^(-2)]`

D

`[ML^(2)T^(-2)Q^(-1)]`

Text Solution

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The correct Answer is:
To find the dimensional formula for resistivity in terms of mass (M), length (L), time (T), and charge (Q), we will follow these steps: ### Step 1: Understand the relationship between resistivity, resistance, area, and length. The formula for resistance (R) is given by: \[ R = \rho \frac{L}{A} \] Where: - \( \rho \) is the resistivity, - \( L \) is the length, - \( A \) is the area of cross-section. From this, we can rearrange the formula to express resistivity: \[ \rho = R \frac{A}{L} \] ### Step 2: Determine the dimensions of resistance (R). Resistance is defined as the ratio of voltage (V) to current (I): \[ R = \frac{V}{I} \] ### Step 3: Find the dimensions of voltage (V). Voltage is defined as work done (W) per unit charge (Q): \[ V = \frac{W}{Q} \] The dimensions of work done (W) are given by: \[ W = \text{Force} \times \text{Distance} = (MLT^{-2}) \times L = ML^2T^{-2} \] Thus, the dimensions of voltage become: \[ V = \frac{ML^2T^{-2}}{Q} \] So, the dimensions of voltage are: \[ [V] = ML^2T^{-2}Q^{-1} \] ### Step 4: Find the dimensions of current (I). Current is defined as charge (Q) per unit time (T): \[ I = \frac{Q}{T} \] Thus, the dimensions of current are: \[ [I] = QT^{-1} \] ### Step 5: Substitute the dimensions of voltage and current into the resistance formula. Now, substituting the dimensions of voltage and current into the resistance formula: \[ R = \frac{[V]}{[I]} = \frac{ML^2T^{-2}Q^{-1}}{QT^{-1}} \] This simplifies to: \[ [R] = \frac{ML^2T^{-2}Q^{-1}}{QT^{-1}} = ML^2T^{-1}Q^{-2} \] ### Step 6: Substitute the dimensions of resistance, area, and length into the resistivity formula. Now we have: - Dimensions of resistance \( [R] = ML^2T^{-1}Q^{-2} \) - Dimensions of area \( [A] = L^2 \) - Dimensions of length \( [L] = L \) Substituting these into the resistivity formula: \[ \rho = R \frac{A}{L} = \left(ML^2T^{-1}Q^{-2}\right) \cdot \frac{L^2}{L} \] This simplifies to: \[ \rho = ML^2T^{-1}Q^{-2} \cdot L = ML^3T^{-1}Q^{-2} \] ### Final Result Thus, the dimensional formula for resistivity \( \rho \) is: \[ [\rho] = ML^3T^{-1}Q^{-2} \]

To find the dimensional formula for resistivity in terms of mass (M), length (L), time (T), and charge (Q), we will follow these steps: ### Step 1: Understand the relationship between resistivity, resistance, area, and length. The formula for resistance (R) is given by: \[ R = \rho \frac{L}{A} \] Where: - \( \rho \) is the resistivity, - \( L \) is the length, ...
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DC PANDEY ENGLISH-UNITS, DIMENSIONS & ERROR ANALYSIS -Check Point 1.1
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