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If 'muscle times speed equals power', th...

If 'muscle times speed equals power', then what is the ratio of the SI unit and the CGS unit of muscle?

A

`10^(5)`

B

`10^(3)`

C

`10^(7)`

D

`10^(-5)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the ratio of the SI unit of muscle to the CGS unit of muscle, given that "muscle times speed equals power". ### Step-by-Step Solution: 1. **Understanding the Relationship**: We start with the equation given in the question: \[ \text{Muscle} \times \text{Speed} = \text{Power} \] This implies that: \[ \text{Muscle} = \frac{\text{Power}}{\text{Speed}} \] 2. **Units of Power and Speed**: - The SI unit of power is the watt (W), which is equivalent to joules per second (J/s). - The SI unit of speed is meters per second (m/s). 3. **Expressing Power in SI Units**: The SI unit of work (energy) is joules (J), where: \[ 1 \text{ J} = 1 \text{ kg} \cdot \text{m}^2/\text{s}^2 \] Therefore, the SI unit of power can be expressed as: \[ 1 \text{ W} = 1 \text{ J/s} = 1 \text{ kg} \cdot \text{m}^2/\text{s}^3 \] 4. **Substituting Units into the Muscle Equation**: Now substituting the units of power and speed into the muscle equation: \[ \text{Muscle (SI)} = \frac{1 \text{ W}}{1 \text{ m/s}} = \frac{1 \text{ kg} \cdot \text{m}^2/\text{s}^3}{1 \text{ m/s}} = 1 \text{ kg} \cdot \text{m/s}^2 \] Thus, the SI unit of muscle is equivalent to newtons (N), where: \[ 1 \text{ N} = 1 \text{ kg} \cdot \text{m/s}^2 \] 5. **Finding the CGS Unit of Muscle**: In the CGS system, the unit of force is the dyne, where: \[ 1 \text{ dyne} = 1 \text{ g} \cdot \text{cm/s}^2 \] To convert from SI to CGS: \[ 1 \text{ kg} = 10^3 \text{ g} \] \[ 1 \text{ m} = 10^2 \text{ cm} \] Therefore, the conversion of newtons to dynes is: \[ 1 \text{ N} = 10^3 \text{ g} \cdot \frac{10^2 \text{ cm}}{(1 \text{s})^2} = 10^5 \text{ dyne} \] 6. **Calculating the Ratio**: Now we have: - SI unit of muscle = 1 N = \(10^5\) dyne - CGS unit of muscle = 1 dyne Thus, the ratio of the SI unit to the CGS unit of muscle is: \[ \text{Ratio} = \frac{10^5 \text{ dyne}}{1 \text{ dyne}} = 10^5 \] ### Final Answer: The ratio of the SI unit to the CGS unit of muscle is \(10^5\).

To solve the problem, we need to find the ratio of the SI unit of muscle to the CGS unit of muscle, given that "muscle times speed equals power". ### Step-by-Step Solution: 1. **Understanding the Relationship**: We start with the equation given in the question: \[ \text{Muscle} \times \text{Speed} = \text{Power} ...
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DC PANDEY ENGLISH-UNITS, DIMENSIONS & ERROR ANALYSIS -Check Point 1.1
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