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The length , breadth , and thickness of ...

The length , breadth , and thickness of a metal sheet are `4.234 m , 1.005 m , and 2.01 cm`, respectively. Give the area and volume of the sheet to the correct number of significant figures.

A

`0.0855"m"^(3)`

B

`0.086"m"^(3)`

C

`0.08556"m"^(3)`

D

`0.08"m"^(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to calculate the area and volume of the metal sheet using the given dimensions. We will also ensure to express the final answers in the correct number of significant figures. ### Step 1: Convert all measurements to the same unit The dimensions given are: - Length (L) = 4.234 m - Breadth (B) = 1.005 m - Thickness (T) = 2.01 cm First, we need to convert the thickness from centimeters to meters: \[ T = 2.01 \, \text{cm} = \frac{2.01}{100} \, \text{m} = 0.0201 \, \text{m} \] ### Step 2: Calculate the area The area of the metal sheet can be calculated using the formula: \[ \text{Area} = 2(L \times B + B \times T + T \times L) \] Now substituting the values: 1. Calculate \( L \times B \): \[ L \times B = 4.234 \, \text{m} \times 1.005 \, \text{m} = 4.26217 \, \text{m}^2 \] 2. Calculate \( B \times T \): \[ B \times T = 1.005 \, \text{m} \times 0.0201 \, \text{m} = 0.020201 \, \text{m}^2 \] 3. Calculate \( T \times L \): \[ T \times L = 0.0201 \, \text{m} \times 4.234 \, \text{m} = 0.0850 \, \text{m}^2 \] Now, summing these areas: \[ \text{Total Area} = 4.26217 + 0.020201 + 0.0850 = 4.367371 \, \text{m}^2 \] Finally, multiply by 2: \[ \text{Area} = 2 \times 4.367371 = 8.734742 \, \text{m}^2 \] ### Step 3: Determine significant figures for area The least number of significant figures in the measurements is 3 (from 2.01 cm). Therefore, we round the area to 3 significant figures: \[ \text{Area} \approx 8.73 \, \text{m}^2 \] ### Step 4: Calculate the volume The volume of the metal sheet can be calculated using the formula: \[ \text{Volume} = L \times B \times T \] Substituting the values: \[ \text{Volume} = 4.234 \, \text{m} \times 1.005 \, \text{m} \times 0.0201 \, \text{m} \] Calculating: 1. Calculate \( L \times B \): \[ L \times B = 4.234 \times 1.005 = 4.26217 \, \text{m}^2 \] 2. Now multiply by \( T \): \[ \text{Volume} = 4.26217 \, \text{m}^2 \times 0.0201 \, \text{m} = 0.0858 \, \text{m}^3 \] ### Step 5: Determine significant figures for volume The least number of significant figures in the measurements is 3 (from 2.01 cm). Therefore, we round the volume to 3 significant figures: \[ \text{Volume} \approx 0.0858 \, \text{m}^3 \] ### Final Answers: - Area = \( 8.73 \, \text{m}^2 \) - Volume = \( 0.0858 \, \text{m}^3 \)
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