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Velocity v is given by v=at^(2)+bt+c, wh...

Velocity `v` is given by `v=at^(2)+bt+c`, where `t` is time. What are the dimensions of `a, b and c` respectively?

A

`["LT"^(-3)],["LT"^(-2)]and["LT"^(-1)]`

B

`["LT"^(-1)],["LT"^(-2)]and["LT"^(-3)]`

C

`["LT"^(-2)],["LT"^(-3)]and["LT"^(-1)]`

D

`["LT"^(-1)],["LT"^(-3)]and["LT"^(-2)]`

Text Solution

Verified by Experts

The correct Answer is:
A

Dimensions of velocity are `["V"]=["L"]["T"^(-1)]`
So, deminsions of `["at"^(2)]=["LT"^(-1)]`
`rArr" "["a"]["T"^(2)]=["LT"^(-1)]`
`rArr" "["a"]=["LT"^(-3)]`
Dimensions of `["bt"]=["LT"^(-1)]rArr["b"]["T"]=["LT"^(-1)]`
`rArr" "["b"]=["LT"^(-2)]`
Dimensions of `["c"]=["LT"^(-1)]`
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