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Using mass (M), length (L), time (T) and...

Using mass (M), length (L), time (T) and current (A) as fundamental quantities, the dimensions of permeability are :

A

`["M"^(-1)"LT"^(2)"A"]`

B

`["ML"^(2)"T"^(-2)"A"^(-1)]`

C

`["MLT"^(-2)"A"^(-2)]`

D

`["MLT"^(-1)"A"^(-1)]`

Text Solution

Verified by Experts

The correct Answer is:
C
`B=muNIrArrmu=(B)/(NI)`
`Bqv=F`
`rArr" "B=(F)/(qv)" so "mu=(F)/(qvNI)`
`mu=["MLT"^(-2)"A"^(-2)]`
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