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If E, M, L and G denote energy, mass, an...

If E, M, L and G denote energy, mass, angular momentum and gravitational constant repectively then the quantity `(E^(2)L^(2)//M^(5)G^(2))` has the dimensions of :-

A

angle

B

length

C

mass

D

None of these

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To solve the problem, we need to determine the dimensions of the quantity \(\frac{E^2 L^2}{M^5 G^2}\) using the known dimensions of energy (E), mass (M), angular momentum (L), and the gravitational constant (G). ### Step 1: Identify the dimensions of each quantity 1. **Energy (E)**: The dimension of energy is given by: \[ [E] = [\text{Work}] = M L^2 T^{-2} \] 2. **Mass (M)**: The dimension of mass is: \[ [M] = M \] 3. **Angular Momentum (L)**: The dimension of angular momentum is: \[ [L] = M L^2 T^{-1} \] 4. **Gravitational Constant (G)**: The dimension of the gravitational constant is: \[ [G] = M^{-1} L^3 T^{-2} \] ### Step 2: Substitute the dimensions into the expression Now, we substitute the dimensions into the expression \(\frac{E^2 L^2}{M^5 G^2}\): 1. **Calculate \(E^2\)**: \[ [E^2] = (M L^2 T^{-2})^2 = M^2 L^4 T^{-4} \] 2. **Calculate \(L^2\)**: \[ [L^2] = (M L^2 T^{-1})^2 = M^2 L^4 T^{-2} \] 3. **Calculate \(M^5\)**: \[ [M^5] = M^5 \] 4. **Calculate \(G^2\)**: \[ [G^2] = (M^{-1} L^3 T^{-2})^2 = M^{-2} L^6 T^{-4} \] ### Step 3: Combine the dimensions Now, we can combine these dimensions in the expression: \[ \frac{E^2 L^2}{M^5 G^2} = \frac{(M^2 L^4 T^{-4})(M L^2 T^{-2})}{M^5 (M^{-2} L^6 T^{-4})} \] ### Step 4: Simplify the expression 1. **Numerator**: \[ [\text{Numerator}] = M^2 L^4 T^{-4} \cdot M L^2 T^{-2} = M^{2+1} L^{4+2} T^{-4-2} = M^3 L^6 T^{-6} \] 2. **Denominator**: \[ [\text{Denominator}] = M^5 \cdot M^{-2} L^6 T^{-4} = M^{5-2} L^6 T^{-4} = M^3 L^6 T^{-4} \] ### Step 5: Final dimension calculation Now we can simplify: \[ \frac{M^3 L^6 T^{-6}}{M^3 L^6 T^{-4}} = M^{3-3} L^{6-6} T^{-6+4} = M^0 L^0 T^{-2} = T^{-2} \] ### Conclusion The dimensions of the quantity \(\frac{E^2 L^2}{M^5 G^2}\) are \(T^{-2}\), which corresponds to the dimension of acceleration or frequency. ### Final Answer The quantity \(\frac{E^2 L^2}{M^5 G^2}\) has the dimensions of **none of the given options** (angle, length, mass). ---

To solve the problem, we need to determine the dimensions of the quantity \(\frac{E^2 L^2}{M^5 G^2}\) using the known dimensions of energy (E), mass (M), angular momentum (L), and the gravitational constant (G). ### Step 1: Identify the dimensions of each quantity 1. **Energy (E)**: The dimension of energy is given by: \[ [E] = [\text{Work}] = M L^2 T^{-2} \] ...
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