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If the unit of force is 1 kN, unit of le...

If the unit of force is 1 kN, unit of length 1 km and unit of time is 100s, what will be the unit of mass?

A

1000 kg

B

1 kg

C

10000 kg

D

100 kg

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the unit of mass given the units of force, length, and time. We will use the relationship between force, mass, and acceleration. ### Step-by-Step Solution: 1. **Identify the Given Units:** - Unit of Force (F) = 1 kN = 1000 N - Unit of Length (L) = 1 km = 1000 m - Unit of Time (T) = 100 s 2. **Recall the Formula for Force:** The formula for force is given by: \[ F = m \cdot a \] where \( m \) is mass and \( a \) is acceleration. 3. **Express Acceleration in Terms of Length and Time:** Acceleration (a) is defined as: \[ a = \frac{L}{T^2} \] Substituting the given units: \[ a = \frac{1 \text{ km}}{(100 \text{ s})^2} = \frac{1000 \text{ m}}{10000 \text{ s}^2} = \frac{1000}{10000} \text{ m/s}^2 = 0.1 \text{ m/s}^2 \] 4. **Substituting Values into the Force Equation:** Now substituting the values of force and acceleration into the force equation: \[ 1000 \text{ N} = m \cdot 0.1 \text{ m/s}^2 \] 5. **Solving for Mass (m):** Rearranging the equation to solve for mass: \[ m = \frac{1000 \text{ N}}{0.1 \text{ m/s}^2} = 10000 \text{ kg} \] 6. **Conclusion:** Therefore, the unit of mass is: \[ m = 10^4 \text{ kg} \] ### Final Answer: The unit of mass is **10,000 kg** or \( 10^4 \text{ kg} \). ---

To solve the problem, we need to find the unit of mass given the units of force, length, and time. We will use the relationship between force, mass, and acceleration. ### Step-by-Step Solution: 1. **Identify the Given Units:** - Unit of Force (F) = 1 kN = 1000 N - Unit of Length (L) = 1 km = 1000 m - Unit of Time (T) = 100 s ...
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Knowledge Check

  • A new system of units is proposed in which unit of mass is alpha kg, unit of length beta m and unit of time gamma s. How much will 5 J measure in this new system ?

    A
    `5alphabeta^(2)gamma^(-2)`
    B
    `5alpha^(-1)beta^(-2)gamma^(2)`
    C
    `5alpha^(-2)beta^(-1)gamma^(-2)`
    D
    `5alpha^(-1)beta^(2)gamma^(2)`
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