Home
Class 11
PHYSICS
The quantities A and B are related by th...

The quantities `A and B` are related by the relation, `m=A//B`, where `m` is the linear density and `A` is the force. The dimensions of `B` are of

A

pressure

B

latent heat

C

work

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the dimensions of the quantity \( B \) given the relationship \( m = \frac{A}{B} \), where \( m \) is the linear density and \( A \) is the force. ### Step-by-Step Solution: 1. **Understanding the Relationship**: We start with the equation: \[ m = \frac{A}{B} \] Here, \( m \) is the linear density, \( A \) is the force, and \( B \) is the quantity whose dimensions we need to find. 2. **Expressing Linear Density**: Linear density \( m \) is defined as mass per unit length. Therefore, we can express it as: \[ m = \frac{\text{mass}}{\text{length}} = \frac{M}{L} \] where \( M \) is the dimension of mass and \( L \) is the dimension of length. 3. **Dimensional Formula of Force**: The dimensional formula for force \( A \) is given by Newton's second law, which states that force is mass times acceleration: \[ A = \text{mass} \times \text{acceleration} = M \cdot (LT^{-2}) = MLT^{-2} \] 4. **Substituting into the Equation**: Now, substituting the dimensional formulas into the equation \( m = \frac{A}{B} \): \[ \frac{M}{L} = \frac{MLT^{-2}}{B} \] 5. **Rearranging for \( B \)**: Rearranging the equation to solve for \( B \) gives us: \[ B = \frac{A}{m} = \frac{MLT^{-2}}{\frac{M}{L}} = \frac{MLT^{-2} \cdot L}{M} = L^2T^{-2} \] 6. **Identifying the Dimensions of \( B \)**: The dimensional formula we derived for \( B \) is: \[ [B] = L^2T^{-2} \] 7. **Matching with Given Options**: We need to identify which of the given options corresponds to the dimensional formula \( L^2T^{-2} \). The options provided are: - Pressure - Latent heat - Work - None of these The dimensional formula for latent heat is also \( L^2T^{-2} \), as it is defined as heat per unit mass. Therefore, the correct answer is: \[ \text{Latent heat} \] ### Final Answer: The dimensions of \( B \) are of **latent heat**.

To solve the problem, we need to find the dimensions of the quantity \( B \) given the relationship \( m = \frac{A}{B} \), where \( m \) is the linear density and \( A \) is the force. ### Step-by-Step Solution: 1. **Understanding the Relationship**: We start with the equation: \[ m = \frac{A}{B} ...
Promotional Banner

Topper's Solved these Questions

  • UNITS, DIMENSIONS & ERROR ANALYSIS

    DC PANDEY ENGLISH|Exercise Match the column|6 Videos
  • UNIT AND DIMENSIONS

    DC PANDEY ENGLISH|Exercise Assertion And Reason|2 Videos
  • VECTORS

    DC PANDEY ENGLISH|Exercise Medical enrances gallery|9 Videos

Similar Questions

Explore conceptually related problems

The quantities A and B are related by the relation A//B = m , where m is the linear mass density and A is the force , the dimensions of B will be

The quantities P and Q are related by P/Q = mu where mu is the linear mass density and Q is specific latent heat. Then dimension of P will be same as

B.O.D is related to

The relation between force F and density d is F=(x)/(sqrt(d)) . The dimension of x is

Write the dimensions of a and b in the relation , P = (b-x^(2))/(at) , where P is power ,x is distance and t is time

Write the dimensions of a and b in the relation , P = (b-x^(2))/(at) , where P is power ,x is distance and t is time

In the relation F=G M m//d^(2) , the quantity G

In the relation F=G M m//d^(2) , the quantity G

The relation between Y. eta and B is

In electromagnetic theory, the electric and magnetic phenomena are related to each other. Therefore, the dimensions of electric and magnetic quantities must also be related to each other. In the questions below, [E] and [B] stand for dimensions of electric and magnetic fields respectively. While [ in_(0)] and [mu_(0)] stand for dimensions of the permittivity and permeability of free space respectively. [L] and [T] are dimensions of length and time respectively. All the quantities are given in SI units. The relation between [E] adn [B] is :-

DC PANDEY ENGLISH-UNITS, DIMENSIONS & ERROR ANALYSIS -Medical entrances gallery
  1. The dimensional formula for Reynold's number is

    Text Solution

    |

  2. The relation between force F and density d is F=(x)/(sqrt(d)). The d...

    Text Solution

    |

  3. In which of the following pairs, the two physical quantities have diff...

    Text Solution

    |

  4. If the absoulte errors in two physical quantites A and B are a and b r...

    Text Solution

    |

  5. If force (F), velocity (V) and time (T) are taken as fundamental units...

    Text Solution

    |

  6. If the unit of force is 1 kN, unit of length 1 km and unit of time is ...

    Text Solution

    |

  7. The dimensional formula for magnetic flux is

    Text Solution

    |

  8. The dimensional formula for electric field is

    Text Solution

    |

  9. The quantity [(nh)//(2piqB)]^(1//2) where n is a positive integer, h i...

    Text Solution

    |

  10. In an experiment four quantities a,b,c and d are measure with percenta...

    Text Solution

    |

  11. Which of the following physical quantity unit is not a fundamental uni...

    Text Solution

    |

  12. The dimensional formula for rate of doing work is

    Text Solution

    |

  13. The density of glass is "2.8 gram"//"cc" in CGS system. The value of d...

    Text Solution

    |

  14. The dimensional formula of electric potential is

    Text Solution

    |

  15. In the equation ((1)/(pbeta))=(y)/(k(B)T), where p is the pressure, y ...

    Text Solution

    |

  16. Which one of the following is not correct ?

    Text Solution

    |

  17. If I is moment of inertia, F is force, v is velocity, E is energy and ...

    Text Solution

    |

  18. A physical quantity X is give by the relation X = (2h^(3)I^(2))/(2sqrt...

    Text Solution

    |

  19. The quantities A and B are related by the relation, m=A//B, where m is...

    Text Solution

    |

  20. A physical quantity is represented by X=M^(a)L^(b)T^(-c).If the percen...

    Text Solution

    |