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Find the sum of vector A and B as shown...

Find the sum of vector A and B as shown in the figure ,also find the direction of sum vector. Given A=4unit and B=3 unit .

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According to the question ,we draw the following figure .

Resultant of the vectors A and B
`R=sqrt(A^(2)+B^(2) +2AB costheta)`
`=sqrt(16+9+2xx4xx3cos60^(@))=sqrt(37)unit`
`therefore`Direction of the sum vector ,
`tanalpha=(Bsintheta)/(A+Bcostheta)= (3sin60^(@))/(4+3cos60^(@))=0.472`
`alpha=tan^(-1)(0.472)=25.3^(@)`
Thus resultant of `|A|and |B|` is `sqrt(37)` unit at angle `25.3^(@)` from A in the direction shown in figure .
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