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What vector must be added to the two vec...

What vector must be added to the two vectors `2hati-hatj+3hatk` and `3hati-2hatj-2hatk`, so that the resultant may be a unit vector along `z`- axis

A

`5hati +hatk`

B

`-5hati +3hatj`

C

`3hati +5hatk`

D

`-3hati +2hatk`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find a vector \( \vec{C} \) that, when added to the two given vectors \( \vec{A} \) and \( \vec{B} \), results in a unit vector along the z-axis. ### Step-by-Step Solution: 1. **Identify the Given Vectors:** - Let \( \vec{A} = 2\hat{i} - \hat{j} + 3\hat{k} \) - Let \( \vec{B} = 3\hat{i} - 2\hat{j} - 2\hat{k} \) 2. **Add the Two Vectors:** - We first find the resultant vector \( \vec{R} = \vec{A} + \vec{B} \). - Performing the addition: \[ \vec{R} = (2\hat{i} + 3\hat{i}) + (-\hat{j} - 2\hat{j}) + (3\hat{k} - 2\hat{k}) \] \[ \vec{R} = (2 + 3)\hat{i} + (-1 - 2)\hat{j} + (3 - 2)\hat{k} \] \[ \vec{R} = 5\hat{i} - 3\hat{j} + 1\hat{k} \] 3. **Set Up the Equation for the Resultant Vector:** - We want the resultant vector \( \vec{R} + \vec{C} \) to equal a unit vector along the z-axis, which can be represented as \( \hat{k} \). - Therefore, we have: \[ \vec{R} + \vec{C} = \hat{k} \] 4. **Substituting the Resultant Vector:** - Substitute \( \vec{R} \) into the equation: \[ (5\hat{i} - 3\hat{j} + 1\hat{k}) + \vec{C} = \hat{k} \] 5. **Isolate \( \vec{C} \):** - Rearranging gives: \[ \vec{C} = \hat{k} - (5\hat{i} - 3\hat{j} + 1\hat{k}) \] \[ \vec{C} = \hat{k} - 5\hat{i} + 3\hat{j} - 1\hat{k} \] \[ \vec{C} = -5\hat{i} + 3\hat{j} + (1 - 1)\hat{k} \] \[ \vec{C} = -5\hat{i} + 3\hat{j} \] 6. **Final Result:** - The vector \( \vec{C} \) that must be added is: \[ \vec{C} = -5\hat{i} + 3\hat{j} \]

To solve the problem, we need to find a vector \( \vec{C} \) that, when added to the two given vectors \( \vec{A} \) and \( \vec{B} \), results in a unit vector along the z-axis. ### Step-by-Step Solution: 1. **Identify the Given Vectors:** - Let \( \vec{A} = 2\hat{i} - \hat{j} + 3\hat{k} \) - Let \( \vec{B} = 3\hat{i} - 2\hat{j} - 2\hat{k} \) ...
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