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The work done by a force F=(hati+2hatj+3...

The work done by a force `F=(hati+2hatj+3hatk)` N ,to displace a body from position A to position B is [The position vector of A is `r_(1)=(2hati+2hatj+3hatk)m` The position vector of B is ` r_(2)=(3hati+hatj+5hatk)m` ]

A

5 J

B

3 J

C

2 J

D

10 J

Text Solution

Verified by Experts

The correct Answer is:
A
(a) Work done ,`W=F.(r_(2)-r_(1))`
position `r_(2)-r_(1)=hati-hatj+2hatk`
`W=(hati+2hatj +3hatk).(hati-hatj+2hatk)=1-2+6=5J`
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