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Two vectors vec(A) and vec(B) inclined a...

Two vectors `vec(A) and vec(B)` inclined at an angle `theta` have a resultant `vec(R )` which makes an angle `alpha` with `vec(A)`. If the directions of `vec(A) and vec(B)` are interchanged, the resultant will have the same

A

magnitude the same

B

direction reverses and megnitude is doubled

C

magnitude as well as direction

D

Neither

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To solve the problem, we need to analyze the situation with two vectors \( \vec{A} \) and \( \vec{B} \) that are inclined at an angle \( \theta \). The resultant vector \( \vec{R} \) makes an angle \( \alpha \) with \( \vec{A} \). We are tasked with determining what happens to the resultant vector if the directions of \( \vec{A} \) and \( \vec{B} \) are interchanged. ### Step-by-Step Solution: 1. **Understanding the Magnitude of the Resultant Vector**: The magnitude of the resultant vector \( \vec{R} \) when two vectors \( \vec{A} \) and \( \vec{B} \) are inclined at an angle \( \theta \) is given by the formula: \[ R = \sqrt{A^2 + B^2 + 2AB \cos(\theta)} \] Here, \( A \) and \( B \) are the magnitudes of vectors \( \vec{A} \) and \( \vec{B} \), respectively. **Hint**: Remember that the magnitude of the resultant depends on the magnitudes of the individual vectors and the cosine of the angle between them. 2. **Interchanging the Directions of Vectors**: When we interchange the directions of \( \vec{A} \) and \( \vec{B} \), the angle \( \theta \) between them remains the same, and the magnitudes \( A \) and \( B \) also remain unchanged. Therefore, the formula for the magnitude of the resultant vector \( R \) remains the same. **Hint**: Consider how the angle between the vectors and their magnitudes affect the resultant vector's magnitude. 3. **Analyzing the Direction of the Resultant Vector**: The resultant vector \( \vec{R} \) is more inclined towards the vector with the greater magnitude. If \( |\vec{A}| > |\vec{B}| \), then the angle \( \alpha \) between \( \vec{A} \) and \( \vec{R} \) is less than the angle between \( \vec{B} \) and \( \vec{R} \). When we interchange the directions of \( \vec{A} \) and \( \vec{B} \), the resultant vector will still make an angle \( \alpha \) with the new direction of \( \vec{A} \) (which was originally \( \vec{B} \)). However, since the direction of \( \vec{A} \) has changed, the resultant vector \( \vec{R} \) will also change its direction to maintain the same angle \( \alpha \). **Hint**: Think about how the direction of the resultant vector is influenced by the directions of the original vectors. 4. **Conclusion**: Since the magnitude of the resultant vector remains the same but its direction changes when the directions of \( \vec{A} \) and \( \vec{B} \) are interchanged, we conclude that the resultant vector will have the same magnitude but a different direction. Therefore, the correct option is that the resultant vector will have the same magnitude but its direction will change. ### Final Answer: The resultant vector \( \vec{R} \) will have the same magnitude but a different direction when the directions of \( \vec{A} \) and \( \vec{B} \) are interchanged.

To solve the problem, we need to analyze the situation with two vectors \( \vec{A} \) and \( \vec{B} \) that are inclined at an angle \( \theta \). The resultant vector \( \vec{R} \) makes an angle \( \alpha \) with \( \vec{A} \). We are tasked with determining what happens to the resultant vector if the directions of \( \vec{A} \) and \( \vec{B} \) are interchanged. ### Step-by-Step Solution: 1. **Understanding the Magnitude of the Resultant Vector**: The magnitude of the resultant vector \( \vec{R} \) when two vectors \( \vec{A} \) and \( \vec{B} \) are inclined at an angle \( \theta \) is given by the formula: \[ R = \sqrt{A^2 + B^2 + 2AB \cos(\theta)} ...
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