A force of `5 N` acts on a particle along a direction making an angle of `60^(@)` with verticle. Its verticel components is

Options

A. 10N
B. 3 N
C. 4 N
D. 2.5 N

Explanation

To find the vertical component of a force acting at an angle, we can use the following steps:

### Step 1: Identify the given values
- The magnitude of the force \( F \) is \( 5 \, \text{N} \).
- The angle \( \theta \) with the vertical is \( 60^\circ \).

### Step 2: Determine the formula for the vertical component
The vertical component of the force \( F_y \) can be calculated using the cosine of the angle:
\[ F_y = F \cdot \cos(\theta) \]

### Step 3: Substitute the known values into the formula
Substituting the values we have:
\[ F_y = 5 \, \text{N} \cdot \cos(60^\circ) \]

### Step 4: Calculate \( \cos(60^\circ) \)
We know that:
\[ \cos(60^\circ) = \frac{1}{2} \]

### Step 5: Calculate the vertical component
Now substituting \( \cos(60^\circ) \) into the equation:
\[ F_y = 5 \, \text{N} \cdot \frac{1}{2} = \frac{5}{2} \, \text{N} \]

### Step 6: Convert the result to a decimal
\[ F_y = 2.5 \, \text{N} \]

### Conclusion
The vertical component of the force is \( 2.5 \, \text{N} \).