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Let vec(A) = hat(i)A cos theta + hat(j) ...

Let `vec(A) = hat(i)A cos theta + hat(j) sin theta`, be any vector. Another vector `vec(B)` which is normal to `vec(A)` is :

A

`hati B costheta -hatj B sin theta `

B

`hati B sin theta -hatj B cos theta `

C

`hati B sin theta+hatj B cos theta `

D

`hati B sin theta+hatj B cos theta `

Text Solution

Verified by Experts

The correct Answer is:
B
(b) Dot product of two perpendicular vector should be zero .
`thereforeB=hatiBsintheta-hatjBcostheta`
`[:'(hatiAsintheta)(hatiBsin theta-hatjBcostheta)=0]`
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