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Two vectors A and B are such that A+B = ...

Two vectors `A` and `B` are such that `A+B = C` and `A^2 +B^2 = C^2`. If `theta` is the angle between positive direction of `A` and `B`, then the correct statement is

A

`theta=pi`

B

`theta=(2pi)/(3)`

C

`theta=0`

D

`theta=(pi)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
(d) `R=sqrt(A^(2)+B^(2)+2ABcostheta)`
From Eq,(I) We get `R^(2)=C^(2)=A^(2)+B^(2)+2ABcos theta=A^(2)+B^(2)`
`impliescos theta=0impliestheta=(pi)/(2)`
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