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Assertion (A+B).(A-B) is always positv...

Assertion (A+B).(A-B) is always positve.
Reason this is positive If `|A|gt|B|`

A

If both Assetion and Reason are correct but Reason is the correct explanation of Assertion.

B

If both Assetion and Reason are correct but Reason is not the correct explanation of Assertion.

C

If Asserion is true but Reason is false

D

If Asserion is false but Reason is true

Text Solution

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The correct Answer is:
To solve the question, we need to analyze both the assertion and the reason provided. ### Step 1: Understanding the Assertion The assertion states that \((A + B) \cdot (A - B)\) is always positive. We need to evaluate this expression. ### Step 2: Expanding the Dot Product Using the distributive property of the dot product, we can expand the expression: \[ (A + B) \cdot (A - B) = A \cdot A - A \cdot B + B \cdot A - B \cdot B \] Since the dot product is commutative (\(A \cdot B = B \cdot A\)), we can simplify this to: \[ A \cdot A - B \cdot B = |A|^2 - |B|^2 \] ### Step 3: Analyzing the Result The expression \( |A|^2 - |B|^2 \) can be positive, negative, or zero depending on the magnitudes of \(A\) and \(B\): - If \(|A| > |B|\), then \( |A|^2 - |B|^2 > 0\). - If \(|A| < |B|\), then \( |A|^2 - |B|^2 < 0\). - If \(|A| = |B|\), then \( |A|^2 - |B|^2 = 0\). Thus, the assertion that \((A + B) \cdot (A - B)\) is always positive is **false**. ### Step 4: Understanding the Reason The reason states that the expression is positive if \(|A| > |B|\). We have already established that if \(|A| > |B|\), then \((A + B) \cdot (A - B) = |A|^2 - |B|^2 > 0\). This is indeed true. ### Conclusion - The assertion is false because \((A + B) \cdot (A - B)\) is not always positive. - The reason is true because the expression is positive when \(|A| > |B|\). ### Final Answer The answer is: Assertion is false, but reason is true. ---

To solve the question, we need to analyze both the assertion and the reason provided. ### Step 1: Understanding the Assertion The assertion states that \((A + B) \cdot (A - B)\) is always positive. We need to evaluate this expression. ### Step 2: Expanding the Dot Product Using the distributive property of the dot product, we can expand the expression: \[ ...
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