A man starts from his home and walks 50 m towards, then he turns towards east and walks 40 m and then reaches to his office after moving 20 m towards south.
(i) What is the total distance covered by the man from his home to office ?
(ii) What is his displacement from his home to office ?

Explanation

Let O is a point of home then according to the question, the man moves from O to A (50 m) to towards north, then from A to B (40 m) towards east and from B to C (20 m) towadrs south as shown in figure.

(i) Total distance travelled by the man is
`OA+AB+BC=50+40+20=110 m`
(ii) Displacement of the person is OC, which can be calculated by Pythagoras theorem, i.e.,
`OC^(2)=OD^(2)+CD^(2)=(40)^(2)+(30)^(2)`
`=1600+900=2500`
`rArr OC=50 m`