The motion of a particle along a straight line is described by the function `x=(2t -3)^2,` where x is in metres and t is in seconds. Find
(a) the position, velocity and acceleration at `t=2 s.`
(b) the velocity of the particle at origin.

Explanation

To solve the problem step by step, we will analyze the motion of the particle described by the function \( x = (2t - 3)^2 \).

### Part (a): Finding Position, Velocity, and Acceleration at \( t = 2 \, \text{s} \)

1. **Finding Position at \( t = 2 \, \text{s} \)**:
- We substitute \( t = 2 \) into the position function:
\[
x = (2(2) - 3)^2 = (4 - 3)^2 = 1^2 = 1 \, \text{m}
...