A ball is dropped from the top of a tower. After 2 s another ball is thrown vertically downwards with a speed of `40 ms^(-1)`. After how much time and at what distance below the top of tower the balls meet ?

Explanation

To solve the problem step by step, we will analyze the motion of both balls and find the time and distance at which they meet.

### Step 1: Understand the Problem
We have two balls:
- **Ball A** is dropped from the top of the tower (initial velocity \( u_A = 0 \)).
- **Ball B** is thrown downward 2 seconds later with an initial velocity of \( u_B = 40 \, \text{m/s} \).

### Step 2: Define Variables
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