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The distance traversed by a particle mov...

The distance traversed by a particle moving along a straight lne is given by `x = 180t+50t^(2)` metre. The acceleration of the particle is

A

`180 ms^(-2)`

B

`580 ms^(-2)`

C

`100 ms^(-2)`

D

`50 ms^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`x=180t+50t^(2)`
`upsilon=(dx)/(dt)=180+100t`
`a=(d upsilon)/(dt)=100m//s^(2)`
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