Home
Class 11
PHYSICS
The motion of a particle is described by...

The motion of a particle is described by the equation at `u = at`.The distance travelled by the particle in the first 4 seconds

A

`4 a`

B

`12 a`

C

`6 a`

D

`8 a`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the distance traveled by a particle in the first 4 seconds, given that its motion is described by the equation \( u = At \). ### Step-by-Step Solution: 1. **Identify the Given Information:** - The equation of motion is given as \( u = At \). - We need to find the distance traveled in the first 4 seconds. 2. **Determine the Acceleration:** - The velocity \( u \) is a function of time \( t \). - To find the acceleration, we differentiate the velocity with respect to time: \[ a = \frac{du}{dt} = \frac{d(At)}{dt} = A \] - Thus, the acceleration \( a \) is constant and equal to \( A \). 3. **Use the Equation of Motion:** - The equation for distance \( s \) traveled under constant acceleration is: \[ s = ut + \frac{1}{2}at^2 \] - Here, \( u \) is the initial velocity, \( a \) is the acceleration, and \( t \) is the time. 4. **Find the Initial Velocity:** - To find the initial velocity \( u \) at \( t = 0 \): \[ u = A \cdot 0 = 0 \] - Therefore, the initial velocity \( u = 0 \). 5. **Substitute Values into the Equation:** - Now substitute \( u = 0 \), \( a = A \), and \( t = 4 \) seconds into the equation: \[ s = 0 \cdot 4 + \frac{1}{2}A(4^2) \] - Simplifying this gives: \[ s = \frac{1}{2}A \cdot 16 = 8A \] 6. **Conclusion:** - The distance traveled by the particle in the first 4 seconds is: \[ s = 8A \] ### Final Answer: The distance traveled by the particle in the first 4 seconds is \( 8A \). ---

To solve the problem, we need to find the distance traveled by a particle in the first 4 seconds, given that its motion is described by the equation \( u = At \). ### Step-by-Step Solution: 1. **Identify the Given Information:** - The equation of motion is given as \( u = At \). - We need to find the distance traveled in the first 4 seconds. ...
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A PLANE

    DC PANDEY ENGLISH|Exercise Check point 3.5|25 Videos
  • MOTION IN A PLANE

    DC PANDEY ENGLISH|Exercise Check point 3.6|20 Videos
  • MOTION IN A PLANE

    DC PANDEY ENGLISH|Exercise Check point 3.3|10 Videos
  • MOTION

    DC PANDEY ENGLISH|Exercise Medical entrances gallery|19 Videos
  • PROJECTILE MOTION

    DC PANDEY ENGLISH|Exercise Level - 2 Subjective|10 Videos

Similar Questions

Explore conceptually related problems

The position of a particle along x-axis at time t is given by x=1 + t-t^2 . The distance travelled by the particle in first 2 seconds is

The potential energy (in SI units) of a particle of mass 2kg in a conservative field is U=6x-8y . If the initial velocity of the particle is vecu=-1.5hati+2hatj , then find the total distance travelled by the particle in the first two seconds.

A particle moves in a straight line from origin. Its velocity time curve is shown. Find the distance of particle at the =8sec. From the origin and the distance travelled by the particle during first 8 seconds.

Velocity of a particle moving along a straight line at any time 't' is give by V = cos((pi)/(3)t) . Then the distance travelled by the particle in the first two seconds is :

The variation of velocity of a particle with time moving along a straight line is illustrated in the following figure. The distance travelled by the particle in four seconds is.

A particle is moving along the x-axis whose acceleration is given by a= 3x-4 , where x is the location of the particle. At t = 0, the particle is at rest at x = 4//3m . The distance travelled by the particles in 5 s is

A particle starting from rest moves in a straight line with acceleration as shown in the a-t graph. Find the distance (in m) travelled by the particle in the first four seconds from start of its motion. Q

A particle is dropped from the top of a high building 360 m. The distance travelled by the particle in ninth second is (g=10 m//s^(2))

A particle is thrown with any velocity vertically upward, the distance travelled by the particle in first second of its decent is

From the velocity time plot shown in figure find the distance travelled by the particle dureing the first 40 seconds. Also find the average velocity during this period.