A body is projected upwards with a velocity `u`. It passes through a certain point above the ground after `t_(1)`, Find the time after which the body passes through the same point during the journey.

Options

A. `((u)/(g)-t_(1)^(2))`
B. `2((u)/(g)-t_(1))`
C. `((u)/(g)-t_(1))`
D. `((u^(2))/(g^(2))-t_(1))`

Answer

B

Explanation

Velocity of particle of this instant will be `upsilon=(u-g t_(1))`

Now the desired time interval will be `(2upsilon)/(g)`.
or `(2(u-g t_(1)))/(g)=2((u)/(g)-t_(1))`