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The distance time graph of a particle at...

The distance time graph of a particle at time `t` makes angle `45^(@)` with respect to time axis. After `1s`, if makes angle `60^(@)` with respect to time axis. What is the acceleration of the particle?

A

`sqrt(3)-1`

B

`sqrt(3)+1`

C

`sqrt(3)`

D

1

Text Solution

Verified by Experts

The correct Answer is:
A
`upsilon_(i)` = slope of s-t graph = `tan45^(@) = 1 ms^(-1)`
`upsilon_(f)` = slope of s-t graph = `tan 60^(@)=sqrt(3)ms^(-01)`
Now `a_(av)=(upsilon_(f)-upsilon_(i))/(Delta t)=(sqrt(3)-1)/(1)=(sqrt(3)-1)` units
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