`v^(2)` versus s-graph of a particle moving in a straight line is shown in the figure. From the graph some conculsions are drawn. State which statement is wrong ?

Options

A. The given graph shown a uniformly accelerated motion
B. Initial velocity of particle is zero
C. Corresponding s-t graph will be a parabola
D. None of the above

Answer

B

Explanation

For uniformly accelerated motion, `upsilon^(2)=u^(2)+2as`, i.e., `upsilon^(2)` versus s graph is a straight line with intercept `u^(2)` and slope 2 a. Since intercept is non-zero, initial velocity is non-zero.