Home
Class 11
PHYSICS
Two bodies are held separated by 9.8 m v...

Two bodies are held separated by `9.8 m` vertically one above the other. They are released simultaneously to fall freely under gravity. After 2 s the relative distance between them is

A

`4.9 m`

B

`19.6 m`

C

`9.8 m`

D

`392 m`

Text Solution

Verified by Experts

The correct Answer is:
C
Both the particle will fall same distance in same time interva. So, the relative separation will remain unchanged.
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A PLANE

    DC PANDEY ENGLISH|Exercise (A) Taking it together|75 Videos

  • MOTION IN A PLANE

    DC PANDEY ENGLISH|Exercise (B) Meical entrance special format questions (Assertion and reason)|19 Videos

  • MOTION IN A PLANE

    DC PANDEY ENGLISH|Exercise Check point 3.6|20 Videos

  • MOTION

    DC PANDEY ENGLISH|Exercise Medical entrances gallery|19 Videos

  • PROJECTILE MOTION

    DC PANDEY ENGLISH|Exercise Level - 2 Subjective|10 Videos

Similar Questions

Explore conceptually related problems

Two point particles of mass m and 2m are initially separated by a distance 4a. They are then released to become free to move. Find the velocities of both the particles when the distance between them reduces to a.

When two bodies approach each other with the different speeds, the distance between them decreases by 120 m for every one minute. If they are moving in direction, the distance between them increases by 90 m for very one minute. The speeds of the bodies are

Two bodies begin to fall freely from the same height but the second falls T second after the first. The time (after which the first body begins to fall) when the distance between the bodies equals L is

A stone at rest is dropped from a height and falls freely under gravity. Calculate the distance covered by it in the first two seconds. (g = 9.8 m s^(-2) )

A stone is dropped freely while another thrown vertically downward with an initial velocity of 4 m/s from the same point simultaneously. The distance of separation between them will become 30 m after a time of

A body released from a great height and falls freely towards the earth. Another body is released from the same height exactly one second later. Then the separation between the two bodies, two seconds after the release of the second body is

Two bodies are thrown simultaneously from a tower with same initial velocity v_0 : one vertically upwards, the other vertically downwards. The distance between the two bodies after time t is

Two celestial bodies are separated by some distance. If the mass of any one of the bodies is doubled while the mass of other is halved then how far should they be taken so that the gravitational force between them becomes one-fourth ?

Two celestial bodies are separated by some distance. If the mass of any one of the bodies is doubled while the mass of other is halved then how far should they be taken so that the gravitational force between them becomes one-fourth ?

Two particles of combined mass M, placed in space with certain separation are released interaction between the particles is only of gravitational nature and there is no external force present. Acceleration of one particle with respect to the other when separation between them is R, has a magnitude :