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A man can swim at the rate of 5 kmh^(-1)...

A man can swim at the rate of `5 kmh^(-1)` in still water A. One km wide river flows at the rate of ` 3 kmh^(-1)` . The man wishes to swim across the river directly opposite to the starting point. How much time will be take to cross the river

A

`127^(@)`

B

`143^(@)`

C

`120^(@)`

D

`150^(@)`

Text Solution

Verified by Experts

The correct Answer is:
A
`sin theta = (upsilon_(r ))/(upsilon_(br))=(3)/(5)`

`therefore theta = 37^(@)`
The required angle is therefore
`90^(@)+theta=90^(@)+37^(@)=127^(@)`
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