The velocity of body is given as `v = 20 + 0.1 t^2`. The body is undergoing

Options

A. uniform acceleration
B. Uniform retardation
C. Non-uniform acceleration
D. Zero acceleration

Answer

C

Explanation

It is given that
`upsilon = (t^(2))/(10)+20`
Differentiating both sides w.r.t. time, we get
`(d upsilon)/(dt)=(2t)/(10)+0=(t)/(5)`
`therefore` Acceleration, `a=(d upsilon)/(dt)=(t)/(5)ne` constant
Hence, it is a case of non-uniform acceleration.