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What is nature of trajectory of a partic...

What is nature of trajectory of a particle having a uniformly accelerated motion in a plane?

A

`x=sqrt((t+a)/(b))`

B

`x=(t+a)/(b)`

C

`t=sqrt((x+a)/(b))`

D

`x=sqrt(t+a)`

Text Solution

Verified by Experts

The correct Answer is:
C
`t=sqrt((x+a)/(b)) or (x+a)=bt^(2) or x=-a+bt^(2)`
Comparing this equation with genral equation of uniformly accelerated motion,
`s=s_(i)+ut+(1)/(2)at^(2)`
we see that `s_(i)=-a, u=0` and acceleration = 2b.
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DC PANDEY ENGLISH-MOTION IN A PLANE-(A) Taking it together
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