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A particle moves along a straight line. Its position at any instant is given by `x = 32t-(8t^3)/3` where x is in metres and t in seconds. Find the acceleration of the particle at the instant when particle is at rest.

A

`-16ms^(-2)`

B

`-27.6ms^(-2)`

C

`32ms^(-2)`

D

`16ms^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`upsilon=(dx)/(dt)=32-6t^(2), upsilon = 0` at `t = 2.30 s`
At `2.30 s " " a=-27.6ms^(-2)`
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