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A particle starting from rest. Its accel...

A particle starting from rest. Its acceleration (a) versus time (t) is as shown in the figure.
The maximum speed of the particle will be.

A

`110ms^(-1)`

B

`55ms^(-1)`

C

`550ms^(-1)`

D

`660ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
The area under acceleration time given change in velocity.

As acceleration is zero at the end of 11 s.
i.e., `upsilon_(max)=` Area of `DeltaOAB=(1)/(2)xx11xx10=55ms^(-1)`
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