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A particle moving with uniform accelerat...

A particle moving with uniform acceleration has average velocities `nu_1, nu_2` and `nu_3` over the successive intervals of time `t_1, t_2` and `t_3` respectively. The value of `(nu_1 - nu_2)/(nu_2 - nu_3)` will be

A

`(upsilon_(1)-upsilon_(2)):(upsilon_(2)-upsilon_(3))=(t_(1)-t_(2)):(t_(2)+t_(3))`

B

`(upsilon_(1)-upsilon_(2)):(upsilon_(2)-upsilon_(3))=(t_(1)+t_(2)):(t_(2)+t_(3))`

C

`(ipsilon_(1)-upsilon_(2)):(upsilon_(2)-upsilon_(3))=(t_(1)-t_(2)):(t_(1)-t_(3))`

D

`(upsilon_(1)-upsilon_(2)):(upsilon_(2)-upsilon_(2)-upsilon_(3))=(t_(1)-t_(2)):(t_(2)-t_(3))`

Text Solution

Verified by Experts

The correct Answer is:
B

Average velocity in uniformly accelerated motion is given by,
`upsilon_(av)=(s)/(t)=(ut+(1)/(2)at^(2))/(t)=u+(1)/(2)at`
Now, `upsilon_(1)=u+(1)/(2)at_(1), upsilon_(2)=(u+at_(1))+(1)/(2)at_(2)`
and `upsilon_(3)=u+a(t_(1)+t_(2))+(1)/(2)at_(3)`
`therefore upsilon_(1)-upsilon_(2): upsilon_(2)-upsilon_(3)=(t_(1)+t_(2)):(t_(2)+t_(3))`
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