Water drops fall at regular intervals from a tap 5 m above the ground. The third drop is leaving the tap, the instant the first drop touches the ground. How far above the ground is the second drop at that instant. `(g = 10 ms^-2)`

Options

A. `2.50m`
B. `3.75 m`
C. `4.00 m`
D. `1.25 m`

Answer

B

Explanation

Time taken by first drop to reach ground `t = sqrt((2h)/(g)`
`rArr t = sqrt((2xx5)/(10))=1s`
As the water drops fall at regular intervals from a tap therefore time difference between any two drops `=(1)/(2)s`. In this given time, distance of second drop from the tap
`=(1)/(2)g((1)/(2))^(2)=(10)/(8)=1.25 m`
Its distance from the ground `= 5-1.25=3.75 m`