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Two particles `P` and `Q` simulaneously start moving from point `A` with velocities `15m//s` and `20m//s` respectively. The two particles move with acceleration equal in magnitude but opposite in direction. When `P` overtakes `Q` at `B` then its velocity is `30m//s`. Find velocity of `Q` at point `B` ( in m/s).

A

`30 ms^(-1)`

B

`5 ms^(-1)`

C

`20 ms^(-1)`

D

`15 ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B

For `P, 30=15+at` or `at=15ms^(-1)`
For `Q, upsilon = 20 -at` or `upsilon = 20-15=5 ms^(-1)`
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