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A particle located at x = 0 at time t =...

A particle located at `x = 0` at time `t = 0`, starts moving along with the positive x-direction with a velocity v that varies as ` v = alpha sqrt(x)`. The displacement of the particle varies with time as

A

t

B

`t^(1//2)`

C

`t^(3)`

D

`t^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D

`upsilon=alpha sqrt(x) rArr (dx)/(dt) = alpha sqrt(x)`
`rArr (dx)/(sqrt(x))=alpha dt`
By integrating both sides
`int x^(-1//2)dx= int alpha dt`
`(sqrt(x))/(1//2)=alpha t rArr sqrt(x)=(1)/(2)alpha t`
`rArr x=(1)/(4)alpha^(2)t^(2)`
`therefore x prop t^(2)`
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