Home
Class 11
PHYSICS
Assertion : A body of mass 4 kg has an i...

Assertion : A body of mass 4 kg has an initial velocity `5hat(i)ms^(-1)`. It is subjected to a force of `4hat(j)N`. The displacement of body from origin after 4 s will be `21.5 m`.
Reason : The equation `v=u+a t` can be applied to obtain v if a is constant.

A

If both Assertion and Reason are correct and Reason is the correct explanation of assertion.

B

If both Assertion and Reason are correct but Reason in not the correct explanation of Assertion.

C

If Assertion is true but Reason is false.

D

If Assertion is false but Reason is true.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze the assertion and reason provided in the question. ### Step 1: Identify Given Information - Mass of the body, \( m = 4 \, \text{kg} \) - Initial velocity, \( \mathbf{u} = 5 \hat{i} \, \text{m/s} \) - Force acting on the body, \( \mathbf{F} = 4 \hat{j} \, \text{N} \) - Time, \( t = 4 \, \text{s} \) ### Step 2: Calculate Acceleration Using Newton's second law, the acceleration \( \mathbf{a} \) can be calculated as: \[ \mathbf{a} = \frac{\mathbf{F}}{m} \] Substituting the values: \[ \mathbf{a} = \frac{4 \hat{j}}{4} = 1 \hat{j} \, \text{m/s}^2 \] ### Step 3: Calculate Displacement The formula for displacement \( \mathbf{s} \) when initial velocity, acceleration, and time are known is: \[ \mathbf{s} = \mathbf{u} t + \frac{1}{2} \mathbf{a} t^2 \] Substituting the known values: \[ \mathbf{s} = (5 \hat{i}) (4) + \frac{1}{2} (1 \hat{j}) (4^2) \] Calculating each term: \[ \mathbf{s} = 20 \hat{i} + \frac{1}{2} (1 \hat{j}) (16) = 20 \hat{i} + 8 \hat{j} \] Thus, the displacement vector is: \[ \mathbf{s} = 20 \hat{i} + 8 \hat{j} \, \text{m} \] ### Step 4: Calculate Magnitude of Displacement The magnitude of displacement \( s \) can be calculated using the Pythagorean theorem: \[ s = \sqrt{(20)^2 + (8)^2} = \sqrt{400 + 64} = \sqrt{464} \approx 21.5 \, \text{m} \] ### Step 5: Conclusion on Assertion The assertion states that the displacement of the body from the origin after 4 seconds will be \( 21.5 \, \text{m} \). From our calculations, this is indeed true. ### Step 6: Conclusion on Reason The reason states that the equation \( v = u + at \) can be applied to obtain \( v \) if \( a \) is constant. This is also true, but it does not directly explain the assertion regarding displacement. Therefore, while both the assertion and reason are true, the reason does not correctly explain the assertion. ### Final Answer - **Assertion**: True - **Reason**: True, but not the correct explanation for the assertion.

To solve the problem step by step, we will analyze the assertion and reason provided in the question. ### Step 1: Identify Given Information - Mass of the body, \( m = 4 \, \text{kg} \) - Initial velocity, \( \mathbf{u} = 5 \hat{i} \, \text{m/s} \) - Force acting on the body, \( \mathbf{F} = 4 \hat{j} \, \text{N} \) - Time, \( t = 4 \, \text{s} \) ...
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A PLANE

    DC PANDEY ENGLISH|Exercise (B) Meical entrance special format questions (Mathch the columns)|6 Videos
  • MOTION IN A PLANE

    DC PANDEY ENGLISH|Exercise (C )Medical entrances gallery|32 Videos
  • MOTION IN A PLANE

    DC PANDEY ENGLISH|Exercise (A) Taking it together|75 Videos
  • MOTION

    DC PANDEY ENGLISH|Exercise Medical entrances gallery|19 Videos
  • PROJECTILE MOTION

    DC PANDEY ENGLISH|Exercise Level - 2 Subjective|10 Videos

Similar Questions

Explore conceptually related problems

A body mass 2kg has an initial velocity of 3 metre//sec along OE and it is subject to a force of 4N in a direction perpendicular to OE. The distance of body from O after 4 sec will be:

A body mass 2kg has an initial velocity of 3 metre//sec along OE and it is subject to a force of 4N in a direction perpendicular to OE. The distance of body from O after 4 sec will be:

A body of mass 2 kg has an initial velocity of 3 m s^-1 along OE and it is subjected to a force of 4 N in O F direction perpendicular to O E . Find the distance of the body from O after 4 s . .

A body of mass (1)/(4) kg moving with velocity 12 m//s is stopped by applying a force of 0.6 N. Then impulse is :-

A body of mass 5 kg initially at rest is subjected to a force of 20 N. What is the kinetic energy acquired by the body at the end of 10 s?

A body of mass 1 kg is moving with velocity 30 ms^(-1) due north. It is acted on by a force of 10 N due east for 4 seconds. Find the velocity of the body after the force ceases to act.

A particle has an initial velocity of 3hat(i) + 4 hat(j) and an acceleration of 0.4 hat(i) + 0.3 hat(j) . Its speed after 10s is :

A particle has an initial velocity of 3hat(i) + 4 hat(j) and an acceleration of 0.4 hat(i) + 0.3 hat(j) . Its speed after 10s is :

An object of mass 2 kg at rest at origin starts moving under the action of a force vec(F)=(3t^(2)hat(i)+4that(j))N The velocity of the object at t = 2 s will be -

A body of mass 5 kg statrs from the origin with an initial velocity vec(u) = (30 hat(i) + 40 hat(j)) ms^(-1) . If a constant force (-6 hat(i) - 5 hat(j))N acts on the body, the time in which the y component of the velocity becomes zero is

DC PANDEY ENGLISH-MOTION IN A PLANE-(B) Meical entrance special format questions (Assertion and reason)
  1. Assertion : Acceleration of a moving particle can change its direction...

    Text Solution

    |

  2. Assertion : An object may have varying speed without having varying ve...

    Text Solution

    |

  3. Assertion : Magnitude of average velocity is equal to average speed, i...

    Text Solution

    |

  4. Assertion : In the equation, s=u+at-(1)/(2)a where, s is the distance ...

    Text Solution

    |

  5. Assertion : A body is momentarily at rest at the instant it reverses t...

    Text Solution

    |

  6. Assertion : The average velocity of a particle having initial and fina...

    Text Solution

    |

  7. Assertion : The upsilon-t graph perpendicular to time axis is not poss...

    Text Solution

    |

  8. Assertion : If velocity - time equation of a particle moving in a stra...

    Text Solution

    |

  9. Assertion : Distance between two particles moving with consant veloci...

    Text Solution

    |

  10. Assertion : In the s-t diagram as shown in figure, the body starts mov...

    Text Solution

    |

  11. Assertion : In the s-t graph as shown in figure, velocity of particle ...

    Text Solution

    |

  12. Assertion : A body of mass 4 kg has an initial velocity 5hat(i)ms^(-1)...

    Text Solution

    |

  13. Assertion : Particle A is moving Eastwards and particle B Northwards w...

    Text Solution

    |

  14. Assertion : On a curved path, average speed of a particle can never be...

    Text Solution

    |

  15. Assertion : If a particle is thrown upwards, then distance travelled i...

    Text Solution

    |

  16. Assertoin : If acceleration of a particle moving in a straight line va...

    Text Solution

    |

  17. Assertion : A lift is ascending with decreasing speed means accelerati...

    Text Solution

    |

  18. Assertion : A body is moving along a straight line such the its veloc...

    Text Solution

    |

  19. Assertion : In the upsilon-t diagram as shown in figure, average veloc...

    Text Solution

    |