Assertion : If a particle is thrown upwards, then distance travelled in last second of upward journey is independent in last second of upward journey is independent of the velocity of projection.
Reason : In last second, distance travelled is `4.9m`. (Taken, `g=9.8 ms^(-2)`)

Options

A. If both Assertion and Reason are correct and Reason is the correct explanation of assertion.
B. If both Assertion and Reason are correct but Reason in not the correct explanation of Assertion.
C. If Assertion is true but Reason is false.
D. If Assertion is false but Reason is true.

Explanation

To solve the problem, we need to analyze the assertion and the reason provided.

### Step 1: Understanding the Assertion
The assertion states that the distance traveled in the last second of the upward journey is independent of the velocity of projection. This means that regardless of how fast the particle is thrown upwards, the distance it covers in the last second before it starts to fall back down should remain constant.

### Step 2: Understanding the Reason
The reason given states that the distance traveled in the last second of the upward journey is 4.9 meters, assuming \( g = 9.8 \, \text{m/s}^2 \). This implies that the distance covered in the last second before the particle starts descending is a fixed value.

### Step 3: Analyzing the Motion
When a particle is thrown upwards, it will eventually come to a stop at its maximum height before descending. The distance traveled in the last second of the upward journey can be calculated using the equations of motion.

### Step 4: Calculating the Distance in the Last Second
To find the distance traveled in the last second of the upward journey, we can use the formula for distance covered during free fall:

\[ s = ut + \frac{1}{2} g t^2 \]

In the last second of the upward journey, the time \( t = 1 \) second, and at the maximum height, the initial velocity \( u = 0 \) (as it momentarily stops before falling). Thus, we can simplify the equation:

\[ s = 0 \cdot 1 + \frac{1}{2} \cdot 9.8 \cdot (1)^2 \]

Calculating this gives:

\[ s = \frac{1}{2} \cdot 9.8 \cdot 1 = 4.9 \, \text{m} \]

### Step 5: Conclusion
From our calculations, we find that the distance traveled in the last second of the upward journey is indeed 4.9 meters. This value does not depend on the initial velocity of projection, confirming the assertion.

### Final Answer
Both the assertion and the reason are correct. The distance traveled in the last second of the upward journey is independent of the velocity of projection and is equal to 4.9 meters.

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