A bullet of mass 0.06 kg moving with a speed of `90ms^(-1)` enters a heavy wooden block and it stopped after a distance of 60 cm. What is the average resistive force exerted by the block on the bullet ?

Explanation

To solve the problem of finding the average resistive force exerted by the block on the bullet, we can follow these steps:

### Step 1: Identify the given values
- Mass of the bullet, \( m = 0.06 \, \text{kg} \)
- Initial speed of the bullet, \( u = 90 \, \text{m/s} \)
- Final speed of the bullet, \( v = 0 \, \text{m/s} \) (since it comes to rest)
- Distance traveled before coming to rest, \( s = 60 \, \text{cm} = 0.6 \, \text{m} \) (convert cm to m)

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