A constant force `F=(hati+3hatj+4hatk)N` acts on a particle and displace it from (-1m,2m,1m)to(2m,-3m,1m).

Explanation

To solve the problem step by step, we will calculate the work done by the force acting on the particle during its displacement.

### Step 1: Identify the initial and final positions
The initial position \( \mathbf{s_1} \) of the particle is given as:
\[ \mathbf{s_1} = (-1 \hat{i} + 2 \hat{j} + 1 \hat{k}) \, \text{m} \]
The final position \( \mathbf{s_2} \) of the particle is given as:
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