In a ballistics demonstration, a police officer fires a bullet mass `50.0g` with speed `200ms^(-1)` on soft plywood of thickness 2.00cm. The bullet emerges only with `10%` of its initial kinetic energy. What is the emergent speed of the bullet ?

Explanation

To solve the problem, we will follow these steps:

### Step 1: Convert the mass of the bullet to kilograms
The mass of the bullet is given as 50.0 g. To convert this to kilograms:
\[ m = \frac{50.0 \, \text{g}}{1000} = 0.050 \, \text{kg} \]

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