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A body of mass 0.8 kg has intial velocit...

A body of mass 0.8 kg has intial velocity `(3hati-4hatj) ms^(-1)` and final velocity `(-6hatj+2hatk) ms^(-1)`. Find change in kinetic energy of the body?

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AI Generated Solution

To find the change in kinetic energy of a body, we can use the formula: \[ \Delta KE = \frac{1}{2} m (v_f^2 - v_i^2) \] where: - \( m \) is the mass of the body, ...
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A cricket ball of mass 150 g has an intial velocity u = (3 hati + 4 hatj)ms^(-1) and a final velocity v = -(3hati + 4 hatj) ms^(-1) , after being hit. The change in momentum (final momentum - initial momentum ) is (in Kg ms^(1) )

A cricket ball of mass 150 g has an intial velocity u = (3 hati + 4 hatj)ms^(-1) and a final velocity v = -(3hati + 4 hatj) ms^(-1) , after being hit. The change in momentum (final momentum - initial momentum ) is (in Kg ms^(1) )

Knowledge Check

  • A cricket ball of mass 150 g has an initial velocity bar(u)=(3hati-4hatj)ms^(-1) and a final velocity bar(v)=-(3hati-4hatj)ms^(-1) after being hit. The change in momentum (final momentum -initial momentum) is ("in kg ms"^(-1))

    A
    zero
    B
    `-(0.45hati+0.6hatj)`
    C
    `-(0.9hati+1.2hatj)`
    D
    `-5(hati+hatj)`

  • A body of mass 5 kg starts from the origin with an initial velocity bar(u)=(30hati+40hatj)ms^(-1) .If a constant force (-6hati-5hatj)N acts on the body, the time in velocity, which the y-component of the velocity becomes zero is.

    A
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    B
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