A block of mass `10 kg` is moving in x-direction with a constant speed of `10 m//s`. it is subjected to a retarding force `F=-0.1 x J//m`. During its travel from `x =20m` to `x =30 m`. Its final kinetic energy will be .

Explanation

To solve the problem step by step, we will use the work-energy theorem, which states that the work done on an object is equal to the change in its kinetic energy.

### Step 1: Identify the given values
- Mass of the block, \( m = 10 \, \text{kg} \)
- Initial speed, \( v_i = 10 \, \text{m/s} \)
- Retarding force, \( F = -0.1x \, \text{J/m} \)
- Initial position, \( x_i = 20 \, \text{m} \)
- Final position, \( x_f = 30 \, \text{m} \)
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