Two springs with spring constants ` K _(1) = 1500 N// m`and m `K_(2) = 3000 N//m` are stretched by the same force. The ratio of potential energy stored in spring will be

Explanation

To solve the problem of finding the ratio of potential energy stored in two springs with different spring constants when stretched by the same force, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Spring Constants**:
- Given: \( K_1 = 1500 \, \text{N/m} \) and \( K_2 = 3000 \, \text{N/m} \).

2. **Understand the Formula for Potential Energy**:
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