A body of mass 5 kg is thrown vertically up with a kinetic energy of 490 J. What will be height at which the kinetic energy of the body becomes half of the original value ? (Acceleration due to gravity`=9.8ms^(-2)`)

Explanation

To solve the problem, we need to find the height at which the kinetic energy of the body becomes half of its original value. Let's break down the solution step by step.

### Step 1: Understand the Initial Conditions
The body has a mass \( m = 5 \, \text{kg} \) and is thrown upward with an initial kinetic energy \( KE = 490 \, \text{J} \).

### Step 2: Calculate Half of the Initial Kinetic Energy
Since we need to find the height at which the kinetic energy becomes half of its original value, we calculate:
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