When slow neutrons are incident on a target containing `underset(92)overset(235).U`, a possible fission reaction is
`underset(92)overset(235).U+underset(0)overset(1).nrarr underset(56)overset(141).Ba+underset(36)overset(92).Kr+3_(0)^(1)n`
Estimate the amount of energy released using the following data Given, mass of `underset(92)overset(235).U=235.04 amu`, mass of `underset(0)overset(1).n=1.0087 amu`, mass of `underset(56)overset(141).Ba=140.91 amu`, mass of `underset(36)overset(92).Kr=91.926 amu`, and energy equivalent to 1 amu=931 MeV.

Explanation

To estimate the amount of energy released during the fission reaction of Uranium-235 when slow neutrons are incident, we can follow these steps:

### Step 1: Write down the given data
- Mass of Uranium-235, \( M_u = 235.04 \, \text{amu} \)
- Mass of neutron, \( M_n = 1.0087 \, \text{amu} \)
- Mass of Barium-141, \( M_{Ba} = 140.91 \, \text{amu} \)
- Mass of Krypton-92, \( M_{Kr} = 91.926 \, \text{amu} \)
- Energy equivalent of 1 amu = 931 MeV
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