In unloading grain from the hold of a ship, an elevator lifts the grian through a distance of 12 m. Grain is discharged at the top of the elevator at a rate of 2 kg each second and the discharge speed of each of grain particle is 3 `ms^(-1)`. Find the minimum horsepower of the motor that can elevate grain in this way. (Take g=10 `ms^(-2)`)

Explanation

To solve the problem, we need to calculate the minimum horsepower of the motor required to elevate the grain. We'll follow these steps:

### Step 1: Calculate the Potential Energy Change
The potential energy (PE) change when lifting the grain can be calculated using the formula:
\[ \text{PE} = mgh \]
Where:
- \( m \) = mass of grain lifted per second (2 kg/s)
- \( g \) = acceleration due to gravity (10 m/s²)
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